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Amith Singh

Hello All,
I am using .Net Framework 1.1.
Using Regular Expressions I would like to split a word(inserting a blank
space) in a string if the word is more than N(say 50) characters. I can do
the same using string manipulations. I am just curious using regular
expressions it should be fast and less number of statements.
Thanks,
Amith

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Kevin Spencer

Regular Expressions is not particularly useful in this situation. It's
really a matter of building a new string by using Substring on the original,
and concatenating the portions together.

--
HTH,
Kevin Spencer
..Net Developer
Microsoft MVP
Big things are made up
of lots of little things.

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Karl

Kevin,
Why would you say regular expressions aren't particularly useful? I think
part of the problem is what's being done isn't well explained. This is the
3rd time Amith has asked and each time we get slightly more information. I
agree with you that if you have a single word in a string string x = "blah"
then substring makes sense. But I'm ASSuming that we are talking about
large text fields...in which case I think regular expressions are the right
way (maybe not the only one) to go...

Karl
--
MY ASP.Net tutorials
http://www.openmymind.net/

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Kevin Spencer

> Why would you say regular expressions aren't particularly useful?

I did say "in this situation." I use Regular Expressions "regularly."

However, if you think using Regular Expressions in this case is a good idea,
go ahead and post your solution. :)

--
HTH,
Kevin Spencer
..Net Developer
Microsoft MVP
Big things are made up
of lots of little things.

"Karl" <karl REMOVE @ REMOVE openmymind REMOVEMETOO . ANDME net> wrote in
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Karl

I did in one of the previous threads Amith started asking the same question
:P

but here it is again:

Regex r = new Regex(@"(?<string>\S{50})", RegexOptions.Compiled
|RegexOptions.Multiline | RegexOptions.ExplicitCapture);
string newString = r.Replace(YOURSTRINGHERE, "${string} ");

Karl

--
MY ASP.Net tutorials
http://www.openmymind.net/

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	System.Text.RegularExpressions.Regex
	System.Text.RegularExpressions.RegexOptions

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